1 条题解
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0
#include <bits/stdc++.h> using namespace std; int f[505][505], n; char s[505]; int main() { cin >> n >> s+1; for (int l = 1; l <= n; l++) { for (int i = 1; i+l-1 <= n; i++) { int j = i + l - 1; if (i == j) f[i][j] = 1; else { f[i][j] = f[i+1][j] + 1; for (int k = i+1; k <= j; k++) if (s[i] == s[k]) f[i][j] = min(f[i][j], f[i+1][k] + f[k+1][j]); } } } cout << f[1][n] << endl; return 0; }
- 1
信息
- ID
- 15
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 10
- 标签
- (无)
- 递交数
- 10
- 已通过
- 3
- 上传者