1 条题解

  • 0
    @ 2024-9-2 20:26:23
    #include <bits/stdc++.h>
    using namespace std;
    const int maxn = 5005;
    int dp[maxn][maxn][2], n, c[maxn];
    
    int main() {
        cin >> n;
        for (int i = 1; i <= n; i++) cin >> c[i];
        for (int l = 1; l <= n; l++) {
            for (int i = 1; i+l-1 <= n; i++) {
                int j = i+l-1;
                if (l == 1) dp[i][j][0] = dp[i][j][1] = 0;
                else {
                    dp[i][j][0] = min( dp[i+1][j][0] + (c[i] != c[i+1]) , dp[i+1][j][1] + (c[i] != c[j]) );
                    dp[i][j][1] = min( dp[i][j-1][0] + (c[i] != c[j]) , dp[i][j-1][1] + (c[j-1] != c[j]) );
                }
            }
        }
        cout << min(dp[1][n][0], dp[1][n][1]) << endl;
        return 0;
    }
    
    
    • 1

    信息

    ID
    14
    时间
    1000ms
    内存
    256MiB
    难度
    10
    标签
    (无)
    递交数
    7
    已通过
    2
    上传者